Question

Math trigonometry non right angle help please
ong please guys

Answer 1

well, as I said a while back, Heron's Area formula works for any triangle, so long we have all sides, and in this case we do, since it's not a right-triangle SOH CAH TOA won't work, so let's plug the values in Heron's

`\qquad \textit{Heron's area formula} \\\\ A=√(s(s-a)(s-b)(s-c))\qquad \begin{cases} s=(a+b+c)/(2)\\[-0.5em] \hrulefill\\ a = 12\\ b = 8\\ c = 6\\ s=(12+8+6)/(2)\\ \qquad 13 \end{cases} \\\\\\ A=√(13(13-12)(13-8)(13-6)) \implies A=√(13(1)(5)(7)) \\\\\\ A=√(455)\implies {\Large \begin{array}{llll} A\approx 21.33 \end{array}}~cm^2`