Question

Consider the following system of two linear equations:

4y + 3x = 0
4y - x = 16
What is the point of intersection?

Answer 1

Answer: The two lines intersect at (-4,3)

Explanation:

So our first step would be to turn both of these into standard slope-intercept form.

1.)

4y + 3x = 0

4y = -3x

y = -3/4x

2.)

4y - x = 16

4y = x + 16

y = 1/4x + 4

Now that we have our 2 equations, y = -3/4x and y = 1/4x + 4 we can graph them to get an intersection at (-4,3)