Question

A sample of oxygen at a temperature of 20 °c occupies a volume of 335 ml. How many moles of gas are present if the pressure is 0. 998 atm?.

Answer 1

To determine the number of moles of oxygen gas present, we can use the ideal gas law equation: PV = nRT. Plugging in the given values of P = 0.998 atm, V = 335 mL (convert to liters by dividing by 1000), R = 0.0821 L.atm/(mol.K), and T = 20 + 273.15 K, we can calculate the number of moles of oxygen gas present. Therefore, there are approximately 0.00127 moles of oxygen gas present.

Step-by-step explanation:

To determine the number of moles of oxygen gas present, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Rearranging the equation to solve for n, we have n = PV / RT. Plugging in the given values of P = 0.998 atm, V = 335 mL (convert to liters by dividing by 1000), R = 0.0821 L.atm/(mol.K), and T = 20 + 273.15 K, we can calculate the number of moles of oxygen gas present.

n = (0.998 atm * 0.335 L) / (0.0821 L.atm/(mol.K) * (20 + 273.15) K) = 0.00127 mol

Therefore, there are approximately 0.00127 moles of oxygen gas present.

Answer 2

Us the PV=nRT formula!