Question

a ball is thrown upward with a speed of 50 ft/s from the edge of a cliff that is 2100 ft above the ground. at what time t does the ball hit the ground? (recall that acceleration due to gravity is 32 ft/s2. round your answer to two decimal places or enter an exact answer.)

Answer 1

The ball takes approximately 10.30 seconds to hit the ground.

Step-by-step explanation:

To find the time it takes for the ball to hit the ground, we can use the kinematic equation:

t = sqrt(2h/g)

where h is the initial height and g is the acceleration due to gravity. In this case, the initial height is 2100 ft, and the acceleration due to gravity is 32 ft/s². Plugging these values into the equation, we get:

t = sqrt(2 * 2100 / 32) = sqrt(4200/32) ≈ 10.30 s

So it takes approximately 10.30 seconds for the ball to hit the ground.