Question

the left end of a spring is attached to a wall. when bob pulls on the right end with a 200 nn force, he stretches the spring by 20 cmcm. the same spring is then used for a tug-of-war between bob and carlos. each pulls on his end of the spring with a 200 nn force.

Answer 1

The question involves the concept of Hooke's law and the calculation of the force constant of a spring. When Bob and Carlos pull on the spring with equal forces, the additional force causes further stretch.

Step-by-step explanation:

The question involves the concept of Hooke's law, which states that the force applied to stretch or compress a spring is directly proportional to the displacement.

In this case, when Bob pulls on one end of the spring with a 200 N force, the spring stretches by 20 cm. This means that the force constant of the spring can be calculated as:

k = F/x

k = 200 N / 0.20 m = 1000 N/m

When Carlos also pulls with a 200 N force, the total force exerted on the spring is 400 N. Since the displacement is the same, the spring will stretch a further 20 cm due to the additional force.