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In a classic experiment, a ball (ball 1) is dropped from a specific height. At the same time, an identical ball (ball 2) is launched horizontally from the same height. Which ball hits the ground first?.

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Answer:

Step-by-step explanation:

The answer to the question related to the time for two balls to reach the ground is option C, the two balls will reach the ground at the same time because the horizontal and vertical planes of motion are independent of each other, and they are also released from the same height.

When a ball is dropped, knowing the height we could find the time with the following equation:

(1)

Where:

: is the final height

: is the initial height

: is the initial speed of the ball in the vertical direction = 0 (it is dropped)

g: is the acceleration due to gravity

When the ball is launched horizontally from the same height, we could find the time with equation (1) since the acceleration in the horizontal direction is zero and the initial velocity in the vertical direction is also zero.

The horizontal motion is related to the equation:

(2)

We can notice in both cases that the ball is accelerated only by gravity.

Let's evaluate each statement

A) This statement is incorrect because the path is the same for both cases. The ball is dropped and launched from the same height.

B) This statement is also incorrect. The velocity of the dropped ball is the same as the velocity of the launched ball because the ball is accelerated only by gravity.

C) This statement is correct. We can see that we would get the same time in equation (1) since , , and is the same for the dropped ball and the launched ball.

D) This statement is incorrect. The nature of motion is related to a freefall motion in both cases.

Therefore, the answer is option C.

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