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A force of 10.0N acts between two unequal charges when they are separated by 0.30m. what will be the force between the charges when the distance between them is increased by 0.15m​

1 Answer

4 votes

Answer:

4.44 N

Step-by-step explanation:

10 = G m1 m2 / r^2 G m1 and m2 are constant so:

10 = k /r^2

10 = k / (.30^2 )

.9 = k now increase to .45

F = .9 / (.45^2) = 4.44 N

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