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The unbalanced force on the miners elevator is 60.0 N and the mass of the loaded elevator is 150 kg what is the acceleration of the elevator down the shaft
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The unbalanced force on the miners elevator is 60.0 N and the mass of the loaded elevator is 150 kg what is the acceleration of the elevator down the shaft

User Abhishesh
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1 Answer

5 votes

Answer:

Step-by-step explanation:

F = m*(g - a)

g - a = F / m

a = g - F / m = 10 - 60.0 / 150 = 9.6 m/s²

User Anshu Prateek
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