Question

From the information given in the diagram below, find the coefficient of friction between

the 43 kg box and the surface on which it is pulled. Note that the box is accelerating at
0.79 m/s2.

Answer 1

μ = 0.55

Step-by-step explanation:

Given:

m = 43 kg

a = 0.79 m/s²

F pull = 265 N

_____________

μ - ? Friction coefficient

2 Newton's law:

m·a = Fpull - μ·m·g

μ·m·g = Fpull - m·a

Friction coefficient:

μ = (Fpull - m·a) / (m·g)

μ = (265 - 43·0.79) / (43·9.8) ≈ 0.55