Explanation:
this is a college question ????
and you don't know how to do it ? what happened to you in elementary school ?
there are many different techniques. everybody thinks theirs is the fastest or easiest to understand.
after all, this is just "playing" with numbers, the factors embedded within the dividend.
this is mine. when I was in elementary school, we called this the "long division" :
62.79 ÷ 23 =
we pick the first few positions from the left of the dividend, where we are sure, the divisor fits at least once.
in our case here : 62.
we do an integer divide of 62/23 = 2 (for 3 the dividend would have to be at least 69). this 2 is our first digit of the quotient.
62.79 ÷ 23 = 2
now we multiply the divisor by that digit and subtract the result from the dividend. this gives us a remainder of 16, and we pull down the next position (7) :
62.79 ÷ 23 = 2
- 46
---------
167
now, we pulled the first digit after the decimal point, and we need to set the decimal point there in our quotient :
62.79 ÷ 23 = 2.
- 46
---------
167
now, we repeat the process by integer dividing this new dividend (167) by the divisor (23)
167/23 = 7
this 7 becomes the next digit in our quotient. and we repeat the process of multiplying this by the divisor and subtracting the result from the dividend. this gives us a remainder (6), and we pull down the next digit (9).
62.79 ÷ 23 = 2.7
- 46
---------
167
- 161
----------
69
and again, we repeat by integer dividing the new dividend (69) by the divisor (23)
69/23 = 3
this 3 is the next digit in our quotient.
we multiply it with the divisor and subtract the result from the dividend.
if the remainder is still not 0, we need to repeat the process by pulling the next digit, which would be an invisible 0. and continue.
but luckily, after this the remainder is 0, and we are finished.
62.79 ÷ 23 = 2.73
- 46
---------
167
- 161
----------
69
- 69
--------------
0
so, 62.79 ÷ 23 = 2.73 and 0 remainder.