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Does anyone know how to solve these types of triangles?

Does anyone know how to solve these types of triangles?-example-1
User Blnpwr
by
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1 Answer

4 votes

Answer:

x= 101

Explanation:

Exterior angle of triangle states that the exterior angle of a triangle is the sum of the 2 opposite interior angles. This is abbreviated as 'ext. ∠ of ∆'. Thus using the exterior angle theorem,

x°= 64° +37° (ext. ∠ of ∆)

x°= 101°

x= 101

_____

Alternative method:

Let the third angle in the triangle be y°.

Since the sum of the angles in a triangle is 180°,

y° +64° +37°= 180° (∠ sum of ∆)

Simplify:

y° +101°= 180°

y°= 180° -101°

y°= 79°

The sum of the angles on a straight line is 180°.

x° +y°= 180° (adj. ∠s on a str. line)

Substitute y°= 79°:

x° +79°= 180°

x°= 180° -79°

x°= 101°

x= 101

User Gdawg
by
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