Question

Explain Step By Step how to solve the following equation by factoring:

3x^2+22x-45

Answer 1

`\huge \sf \dag \: Answer :`

`\rm 3 {x}^(2) + 22x - 45`

The values of a, b, and c are obtained, namely

• a = 3, b = 22, c = -45

with the values of a, b, and c above we determine the value of x, then :

`\longmapsto \sf x_(1,2) = \frac{ - b \pm \sqrt{ {b}^(2) - 4ac } }{2a}`

`\longmapsto \sf x_(1,2) = \frac{ - 22 \pm \sqrt{ {22}^(2) - 4(3)( - 45)} }{2(3)}`

`\longmapsto \sf x_(1,2) = ( - 22 \pm √(484 - 4( - 135)) )/(6)`

`\longmapsto \sf x_(1,2) = \frac{ - 22 \pm \sqrt[]{484 + 540} }{6}`

`\longmapsto \sf x_(1,2) = ( - 22 \pm √(1.024) )/(6)`

`\longmapsto \sf x_(1,2) = ( - 22 \pm32)/(6)`

with that we get the values of x, namely :

`\longmapsto \rm x_(1) = \bf (10)/(6) = 1 (2)/(3)`

`\longmapsto \sf x_(2) = \bf - 9`

Solution Set = {1⅔, -9}

-I Hope This Helps!