Question

Three sisters have ages that are consecutive even integers. Find their ages If the sum of twice the youngest and three times the oldest is Pourteen more than four times the middle sister's age

Answer 1

12 ; 13 ; 14

Explanation:

x = sister one

x+ 1 = sister two

x+2 = sister three

2x + 3(x+2) = 4(x+1) + 14

2x + 3x + 6 = 4x + 4 + 14

5x + 6 = 4x + 18

5x - 4x = 18 - 6

x = 12 (sister one)

12 + 1 = 13 (sister two)

12 + 2 = 14 (sister three)