![{ \red{ \boxed{ \pink{ \sf{x = 9}}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/3ewzzsytbmtq6kyi8x2z998bgd23ih80ym.png)
Explanation:
Here, the question is,
![{ \green{ \sf{ {x}^(2) = 81}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/jus5dlgjm2jn7y615nghe31kcfyrsux089.png)
Apply square root on both the sides then,
![{ \green{ \sf{ \cancel { √(x) }^( \cancel2)}}} \: = { \green{ \sf{ √(81)}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ko6cphhvzdezwzmh4gcm0rmfnweuc9cwvu.png)
Now,
![{ \green{ \sf{x = √(81)}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/z7l00xwgylgf61u2cr77ldvvnpg0aq3ha5.png)
We got √81 as answer but what is the perfect square number of 81? That is 9. Same number when multiplied twice to get the resultant number makes a perfect square number. i.e. 9×9 = 81. So, the answer is
![{ \green{ \boxed{ \red{ \tt{x = 9}}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/1y5jzl99un7x4m0060d86n0bir6r4zw3fv.png)