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Factorise fully 7x^3-35

2 Answers

1 vote

Answer: 7(x^3-5)

Explanation:

the common number between 7 and 35 is seven( 7*1=7, 7*5=35)

so with the 7 outside the parenthesis we end up having inside the parenthesis x^3 and 5 because x=1 and 7*1=7 and the 5 because 7*5=35 so if we distribute the seven we would get the original answer

User Howettl
by
7.8k points
7 votes

Answer:


7(x^3-5)

Explanation:

Given expression:


7x^3-35

To factor the given expression, begin by rewriting 35 as 7 · 5:


\implies 7x^3-7 \cdot 5

Now factor out the common term 7:


\implies 7(x^3-5)

User Hassan Hodges
by
8.3k points

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