Question

Given the equation y=x^2+8

Find the cordinates of the vertex it desribes
Find the x intersepts
Find the y intercept
Find the line of symetry

Answer 1

Line of symmetry: -b/2a = 0 because b is 0 and a is 1

y-intercept is when x=0, therefore it is at 8.

x-intercept is when y=0, and you would get sqrt(-8), therefore there are no real zeros for this equation.

Vertex: (0,8)

Explanation:

To find the vertex, plug in the x-value from the line of symmetry because the vertex happens at the line of symmetry. When you set x=0, then the y-value of the vertex is 8, therefore, the vertex is at (0,8).