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URGENT:

suppose that ln5=a and ln11=b. Use properties of logarithms to write the logarithm in terms of a and b. ln 5sqrt55

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The phrase asked:
\ln5โˆš(55)

if ln5=a and ln11=b:


\ln5โˆš(55) =\\\\ \ln5+\ln(55)^{(1)/(2)}=\\\\\\ \ln5+(1)/(2)(\ln55)=\\\\\\ \ln5+(1)/(2)(\ln5.11)=\\\\\\ \ln5+(1)/(2)(\ln5+\ln11)=\\\\\\ a+(1)/(2)(a+b)= (1)/(2)(3a+b)

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theorem 1:


\ln(x.y)= \ln x + \ln y

theorem 2:


\log_a{x^n} = n \cdot \log_a{x}

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