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What volume of hydrogen ( in L ) is produced from the complete reaction of 56.49 g of magnesium metal at STP ( MG = 24.30 g/mol) Mg(s) + 2HCI(aq) ---> MgCI2(aq) + H2(g)
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What volume of hydrogen ( in L ) is produced from the complete reaction of 56.49 g of magnesium metal at STP

( MG = 24.30 g/mol)
Mg(s) + 2HCI(aq) ---> MgCI2(aq) + H2(g)

User Kpratihast
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Answer:

Mg = 24.30 g/mol) Mg(s) + 2HCl(aq) MgCl2(aq) + H2(g) Hint: 1 mole of gas at STP occupies 22.4 L

User Deepti Raghav
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