Question

A 21.5 L sample of gas at 107 kPa has a temperature of 27.2 °C. What is the pressure of the gas

if it is transferred to a 32.6L container at 44.1 °C?

Answer 1

The right answer is "74.516 kPa".

Step-by-step explanation:

The given values are:

V₁ = 21.5 L

V₂ = 32.6L

P₁ = 107 kPa

T₁ =27.2°C+273

T₂ = 44.1 °C+273

As we know,

⇒
`(P_1V_1)/(T_1)= (P_2V_2)/(T_2)`

then,

⇒
`P_2=(P_1V_1T_2)/(T_1V_2)`

On substituting the given values, we get

⇒
`=(107* 21.5* (44.1+273))/((27.2+273)* 32.6)`

⇒
`=(107* 21.5* 317)/(300.2* 32.6)`

⇒
`=(729258.5)/(9786.52)`

⇒
`=74.516 \ kPa`