155,245 views
7 votes
7 votes
The length of a rectangular garden is 3 m greater than the width.the area of the garden is 70 m^2. Find the dimensions of the garden

User Ariel Allon
by
3.0k points

2 Answers

21 votes
21 votes

Answer:

Explanation:

A = L x W

so you know that the length is 3m longer than the width, so you could use a formula to represent that

w = L + 3

you then substitute the second equation into the first to solve for L

70 = L x (l +3)

70 = L^2 + 3l

you could then rearrange the formula and solve for l using the quadratic formula

0 = L^2 + 3l - 70

l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)

l = -3 +- (square root 9 + 280) / 2

l = -3 +- (square root 289) / 2

l = -3 +- 17 / 2

then you solve for the two separate roots

l = -3 + 17 /2

l = 14 / 2

l = 7

or

l = -3 - 17 / 2

l = -20 / 2

l = -10

since a length cannot be negative, this root is not viable. therefore l = 7

to solve for w you would use

w = l + 3

w = 7 + 3

w = 10

hope this helps. :)))

User Emomaliev
by
2.7k points
18 votes
18 votes
Yes it’s crazy
Cause my dad came back with the milk
User Fady Sadek
by
2.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.