Question

A 4 kg particle moves at a constant speed of 2.5 m/s around acircle of radius 2 m. What is its angular momentum about the center of the circle? Answerin units of kg · m2/s. What is its moment of inertia about an axis through the center ofthe circle and perpendicular to the plane of the motion? Answer inunits of kg · m2. What is t

Answer 1

Step-by-step explanation:

Given that,

Mass of the particle, m = 4 kg

Speed of the particle, v = 2.5 m/s

The radius of the circle, r = 2 m

We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :

`L=mvr`

Substitute all the values,

`L=4* 2.5* 2\\\\L=20\ kg{\cdot}m^2s`

So, the angular momentum of the particle is 20 kg-m² s.