Question

Heat in the amount of 100 kJ is transferred directly from a hot reservoir at 1400 K (TH) to a cold reservoir at 600 K. Calculate the entropy change of the two reservoirs. The entropy change of the two reservoirs is kJ/K. Is the increase of entropy principle satisfied

Answer 1

ΔS = - 0.125 Kj/K decreased entropy

Step-by-step explanation:

From ΔH = TΔS => ΔS = ΔH/T

= 100Kj/(600K - 1400K) = - 188Kj/800K = - 0.125 Kj/K

Entropy in the cooler flask would have 'decreased' (i.e.; more ordered state) at 600K.