Answer:
0.0001
Explanation:
The computation of the probability of experiencing such a drop in water pressure is shown below:
Given that
mean = 519,645 gallons
Standard deviation = 71,564 gallons
Now the probability is
= 1 - p (x - mean ÷ standard deviation < 782,238 - 519,645 ÷ 71,564)
= 1 - p(z<3.67)
= 1 - 0.9999
= 0.0001