Question

I need help finding the area

Answer 1

Given :

• Base of triangle = 7 yd
• Height of triangle = 10 yd

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To find:

• Area of triangle

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We know:-

When base and height of triangle is given we use this formula:

`\bigstar \boxed{ \rm Area \: of \: triangle = (base * height)/(2) }`

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So:-

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`\dashrightarrow \sf \: Area \: of \: triangle = (base * height)/(2) \\`

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`\dashrightarrow \sf \: Area \: of \: triangle = (7 * 10)/(2) \\`

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`\dashrightarrow \sf \: Area \: of \: triangle = (7 * 5 *2 )/(2) \\`

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`\dashrightarrow \sf \: Area \: of \: triangle = (7 * 5 *\cancel2 )/(\cancel2) \\`

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`\dashrightarrow \sf \: Area \: of \: triangle = (7 * 5 *1 )/(1) \\`

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`\dashrightarrow \sf \: Area \: of \: triangle =7 * 5`

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`\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^(2) \\`

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`\therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^( \red2) }}`

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know more :-

`\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length* Breadth \\\\ \star\sf Triangle=(1)/(2)* Base* Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\frac {1}{2}* d_1* d_2 \\\\ \star\sf Rhombus =\:\frac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base* Height\\\\ \star\sf Trapezium =\frac {1}{2}(a+b)* Height \\ \\ \star\sf Equilateral\:Triangle=\frac {√(3)}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}`]