Question

The water line from the street to my house is 1 inch diameter and made of PVC (i.e. smooth). The line is roughly 450 ft long. The water pressure in the line at the street is 130 psig. If I flow 10 gpm through the pipe, what pressure would I expect when I get to my house. My house is 10 ft higher in elevation than the water line at the street

Answer 1

The right solution is "126 Psi".

Step-by-step explanation:

The given values are:

P₁ = 130 psig

i.e.,

=
`130* 6.894`

=
`896.22 \ Kpa`

or,

=
`896.22* 10^3 \ Pa`

Z₂ = 10ft

= 3.05 m

`\delta` = 1000 kg/m³

According to the question,

Z₁ = 0

V₁ = V₂

As we know,

⇒
`(P_1)/(\delta_g) +(V_1^2)/(2g) +Z_1=(P_2)/(\delta_g) +(V_2^2)/(2g) +Z_2`

On substituting the values, we get

⇒
`(P_1)/(\delta_g) +0+0=(P_2)/(\delta_g) +0+Z_2`

⇒
`(896.22* 10^3)/(1000* 9.8) =(P_2)/(1000* 9.8) +3.05`

⇒
`P_2=866330 \ P_a`

i.e.,

⇒
`=866330* 0.000145`

⇒
`=126 \ Psi`