Answer:
C. 10 m·s⁻¹
Step-by-step explanation:
The velocity is numerically equal to the area of the figure lying under the acceleration graph
V = 2·1.0 + (1.0 + 3.0)·(6 - 2) / 2 = 2.0 + 4.0·4 / 2 = 10 m·s⁻¹
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