Question

2. A 10kg block of wood is pulled across a level ground by fore of 15N applied at

an angle of 30 degree from the horizontal. How much work is done, if it is moved
to a distance of 3m?
(Note: F applied = 15N x cos 30 degree, cos 30 degree = 0.5)

Answer 1

about 19.49J

Step-by-step explanation:

Work = F × D × Cosine(θ)

Substitute values :D:

Work= 15N x cos 30 degree x 3m x cos 30

Work= 7.5 x 3 x cos 30

Work= about 19.49 joules