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1) 3x(x-3)+x(x-1)=50 2) 4x^2-10x=50 3) 2x^2-5x-25=0 How do you get from steps 1 to 2 to 3?
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Jan 21, 2023
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1) 3x(x-3)+x(x-1)=50
2) 4x^2-10x=50
3) 2x^2-5x-25=0
How do you get from steps 1 to 2 to 3?
Mathematics
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Steve Salowitz
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Explanation:
okok
3x(x-3)+x(x-1)=50
multiply inside the brackets then
3x^2-9x+x^2-x=50
then arrange then according to power and add or subtract
4x^2-10x=50 here is your step 2
take 2 common form LHS as
2(2x^2-5x)=50
then you will get your step 3 as
2x^2-5x=25.....25 comes from 50/2 and 2 is from LHS
Jackpap
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Jan 27, 2023
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Jackpap
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