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How do you write x^2+8x+7 in the complete square method? need help asap!!

2 Answers

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x=4±√23

I Hope this helps!!!
User ErikMD
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3 votes

Answer:

Explanation:

Equation

y = x^2 + 8x + 7 Put brackets around the first two terms

y = (x^2 + 8x) + 7 Take 1/2 the linear term's coefficient (8)

8/2 = 4 Put this result inside the brackets and square

y = (x^2 + 8x + 4^2) + 7 Take - 4^2 and add it to the seven.

y = (x^2 + 8x + 16) + 7 - 16 What you did, did not change the eqiuation

Y = (x^2 + 8x + 16) - 9 The first 3 terms make a perfect square

y = (x + 4)^2 - 9

The minimum should be at - 4,-9 Just to make sure it is, I'll graph the original equation. The y intercept should be at 7 and the two x roots should x = + 3 - 4 and x = -3 - 4. or x = -1 and x = - 7

Let's see if this all checks out.

Graph of original equation.

How do you write x^2+8x+7 in the complete square method? need help asap!!-example-1
User Mdexp
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5.6k points