Answer:
df(t)/dt = 10 - 0.8f(t)
Explanation:
The net rate of change, df(t)/dt = rate in - rate out
The rate in = rate litter forms on ground = 10 g/cm²/yr
Since f(t) is the amount of litter present at time, t, in g/cm² the rate out = rate of decomposition = the percentage rate × f(t) = 80% per year × f(t) = 0.8f(t) g/cm²/yr
Since df(t)/dt = rate in - rate out
df(t)/dt = 10 - 0.8f(t)
So the desired differential equation is
df(t)/dt = 10 - 0.8f(t)