Question

A scuba diver descends in the water at a rate of 23.5 feet per minute for 2.6 minutes. He immediately changes course when he sees a large fish and ascends at a rate of 28 feet per minute for 2 minutes. What is the scuba diver's position relative to sea level after the 4.6 minutes? Enter your answer as a decimal in the box.

Answer 1

Explanation:

t is given that a scuba driver descends in water for 2.8 minutes at a rate of feet per minute.

Let's assume the descending position as negative.

The position at which the scuba driver will be after 2.8 minutes is :

= - feet per minute × 2.8 minutes

= - 57.4 feet

Now , he sees a large fish and changes his direction and starts diving ascending at a rate of 25 feet per minute for 2 minutes.

Let's assume the ascending position as positive.

So , The position at which the scuba driver will be after 2 minutes after seeing large fish is :

= 25 × 2

= 50 feet

So , the scuba diver's position relative to sea level after the 4.8 minutes will be :

= -57.4 + 50

= -7.4 feet

This meant Scuba driver is 7.4 feet below sea level.