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Ƒ(x) = −x² – 10x – 9 Find ƒ(−1)
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4 votes
Ƒ(x) = −x² – 10x – 9
Find ƒ(−1)

User Foxesque
by
3.5k points

1 Answer

5 votes

Answer: 0

Explanation:

ƒ(x) = −x² – 10x – 9

Putting value of x as -1

the function is as followed:

ƒ(-1) = -(-1)^2 - 10 (-1) - 9

ƒ(-1) = -1 +10-9

ƒ(-1) = 9-9

= 0

User Pavlee
by
3.5k points
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