Question

Find the slope, if it exists, of the line containing the pair of points.

(-11,-16) and (-13, -20)

Answer 1

2

Explanation:

(-11, -16) and (-13, -20)

To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(-20 - (-16)) / (-13 - (-11))

Simplify the parentheses.

= (-20 + 16) / (-13 + 11)

= (-4) / (-2)

Simplify the fraction.

-4/-2

4/2

= 2

This is your slope.

Answer 2

Equation of the line - Slope

The points of the slope are, we also apply the formula:

`\huge \boxed{\boldsymbol{\sf{\left \{ {{x_1,y_1} \atop {x_2,y_2}} \right. \iff \ m=(y_2-y_1)/(x_2-x_1) }}}`

The points are:

`\boldsymbol{\sf{\underbrace{x_1=-11} \ \ \ \ \ \ \ \ \ \ \overbrace{y_1=-16} \ \ \ \ \ \ \ \ \ \ \underbrace{x_2=-13} \ \ \ \ \ \ \ \ \ \ \overbrace{y_(2)=-20} }}`

Substitute data into the formula:

`\boldsymbol{\sf{m=(\Delta y)/(\Delta x) \iff \ m=(y_2-y_1)/(x_2-x_1) }}`

`\boldsymbol{\sf{m=(-20-(-16))/(-13-(-11)) }} \\ \\ \\ \boldsymbol{\sf{m=(-4)/(-2) }}\\ \\ \\ \boxed{\boxed{\boldsymbol{\sf{m=2}}}}`

The slope through the points (-11,-16) and (-13, -20) is 2.