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Which equation represents the line that is

perpendicular to the graph of 4x + 3y = 9 and
passes through (-2, 3)?
A. 3x-4y=-18
B. 3x+4y=18
C. 3x-4y=-6
D. 3x+4y=6

1 Answer

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Final answer:

The equation of the line perpendicular to 4x + 3y = 9 and passes through (-2, 3) is 3x - 4y = -18.

Step-by-step explanation:

To find the equation of a line that is perpendicular to the given line, we need to find the negative reciprocal of the slope of the given line. The given line's equation is 4x + 3y = 9, which can be rewritten as y = (-4/3)x + 3. The slope of this line is -4/3, so the perpendicular line will have a slope of 3/4.

Using the equation y - y1 = m(x - x1) with the point (-2, 3), we can substitute the values and the slope into the equation. This gives us y - 3 = (3/4)(x + 2).

After simplifying, the equation becomes 3x - 4y = -18. So, the perpendicular line that passes through (-2, 3) is represented by the equation 3x - 4y = -18, which is option A.

User Joe Slater
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