Question

A 1,500 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car moves from 0 m/s to 27 m/s in 8 sec. What is the acceleration of the car?

Answer 1

3.375 m/s²

Step-by-step explanation:

Using equation of motion:

v = u + at

Here, v = 27m/s & u = 0m/s & t = 8 sec

Let the acceleration be a.

=> 27 = 0 + 8(a)

=> 27/8 = a

=> 3.375 m/s²