What is the resistance in a light bulb that has a 61 Volt battery and a current of 12 Amps?

asked May 14, 2023 235k views

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by PQW

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3 votes

Answer:

5.1 Ω

Step-by-step explanation:

Basic Law v = ir

so v/i = r = 61/12 = 5.1 Ω

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