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Solve: (1+i)^14. And show workings​

1 Answer

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Explanation:

(1 + i)¹⁴ = (1 + i)²×(1 + i)¹² = ((1 + i)²)⁷

(1 + i)² = 1 + 2i - 1 = 2i

((1 + i)²)⁷ = (2i)⁷ = 2⁷×i⁷ = 128×i²×i²×i²×i =

= 128×-1×-1×-1×i = -128i

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