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Solve these two equations simultaneously
7x+y = 1 and 2x² - y = 3

User ElKamina
by
7.8k points

1 Answer

3 votes

Answer:

(- 4, 29 ) and (
(1)/(2), -
(5)/(2) )

Explanation:

7x + y = 1 ( subtract 7x from both sides )

y = 1 - 7x → (1)

2x² - y = 3 → (2)

substitute y = 1 - 7x into (2)

2x² - (1 - 7x) = 3

2x² - 1 + 7x = 3

2x² + 7x - 1 = 3 ( subtract 3 from both sides )

2x² + 7x - 4 = 0 ← in standard form

(x + 4)(2x - 1) = 0 ← in factored form

equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

2x - 1 = 0 ⇒ 2x = 1 ⇒ x =
(1)/(2)

substitute these values into (1) for corresponding values of y

x = - 4 : y = 1 - 7(- 4) = 1 + 28 = 29 ⇒ (- 4, 29 )

x =
(1)/(2) : y = 1 - 7(
(1)/(2) ) = 1 -
(7)/(2) = -
(5)/(2) ⇒ (
(1)/(2), -
(5)/(2) )

User Causita
by
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