160,685 views
28 votes
28 votes
Graph y ≤ (x + 2)^2.

Click on the graph until the correct graph appears.

Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-1
Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-1
Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-2
Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-3
Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-4
User ASpirin
by
2.5k points

2 Answers

11 votes
11 votes

Answer:

its the first one

Explanation:

our vertex is (-2,0)

so replace it in the equation y ≤ (x + 2)^2

so, 0 ≤ (-2 + 2)^2

= 0 ≤ (-4)^2

= 0 ≤ 16

look at that statement, is 0 less than or equal to 16? Yes. Therefore it is correct, so you shade out side of the parabola.

TIP: If the parabola opens up and:

y <, then shade outside.

y >, then shade inside.

Do the opposite if the parabola opens down.

User Alerya
by
3.0k points
9 votes
9 votes

Answer:

the first one is the correct one

Explanation:

a great way to check this is to use demos .com

User Yeats
by
3.1k points
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