95.6k views
3 votes
Calculate the hypotenuse of a right triangle whose legs measure 20 and 18 cm.​

User Bunbun
by
3.7k points

2 Answers

5 votes

Answer: c≈26.91

Step-by-step explanation: c=a2+b2=202+182≈26.90725

User Moudy
by
3.3k points
4 votes

Hello..!

We use the Pythagorean formula:


\sf \red{c {}^(2) } = \blue{ a {}^(2) + b {}^(2) }

We know that once we have the formula we extract the Raised data:


\sf \red{c {}^(2)} = \blue{(20cm) {}^(2) + (18cm) {}^(2) }

Having the Raised data, we will add as a power and we know that:


\sf \red{20 {}^(2) } = \orange{400}


\sf \red{18 {}^(2)} = \orange{324}

So, to solve a power we must multiply squared and then get our result, in this case I added and then increased it by 0


\sf \red{c {}^(2) }= \blue{400cm {}^(2) + 324cm {}^(2) }

We have the results, once that is done we will add.


\sf \red{400 + 324 }= \blue{724}

So, we have the result we just have to put it like this:


\sf\red{c {}^(2) } = \blue{724cm {}^(2) }

Once we have our result, we must take the square root, then the (square "²") automatically disappears.


\sf \red{c =} \green{ √(724cm) }


\sf \red{c }= \orange{ 26.90cm}

So, our result of our problem is:
\orange{ \sf \longmapsto} \sf \blue{ \: 26.90cm}

User Mikus
by
3.8k points