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A ball is thrown vertically upward with an initial velocity of 29. 4 meters per second. What is the maximum height reached by the ball? [neglect friction. ].

1 Answer

4 votes

Answer:

44 m

Step-by-step explanation:

vf = velocity at highest point = 0

vf = vo + at

0 = 29.4 + (-9.81 )t shows t = ~ 3 s

d = vo t + 1/2 a t^2

d = 29.4 ( 3) + 1/2 ( -9.81)(3^2 ) = 44 m

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