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If P = (-1,-1) and Q = (5, 3) are the endpoints of the diameter of a circle, find the equation of the circle. (x - 2)² + (y - [?])² = [ ]

If P = (-1,-1) and Q = (5, 3) are the endpoints of the diameter of a circle, find the equation of the circle. (x - 2)² + (y - [?])² = [ ]
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If P = (-1,-1) and Q = (5, 3) are the

endpoints of the diameter of a circle,
find the equation of the circle.
(x - 2)² + (y - [?])² = [ ]

If P = (-1,-1) and Q = (5, 3) are the endpoints of the diameter of a circle, find-example-1
User Ricardo Moreira
by
7.6k points

1 Answer

4 votes

Answer:

The equation of the circle is (x-2)^2+(y-1)^2=13

Explanation:

User Aclima
by
8.6k points
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