Question

A cheerleader lifts his 68.6 kg partner straight

up off the ground a distance of 0.601 m before
releasing her. Assume the partner’s velocity
is zero at the beginning and the end of the lift.
The acceleration of gravity is 9.8 m/s
2
.
If he does this 30 times, how much work has
he done?
Answer in units of J.

Answer 1

Answer: 12121.2084

Step-by-step explanation:

Answer 2

12 121 J

Step-by-step explanation:

PE gained each time = m g h

now 30 times: 30 mgh = 30 * 68.6 * 9.8 * .601 = 12 121 J