Question

Consider △XYZ Triangle X Y Z is shown. Angle X Z Y is a right angle. What are the ratios of sine, cosine, and tangent for angle Y? sin(Y) = StartFraction X Z Over X Y EndFraction; cos(Y) = StartFraction Y Z Over X Z EndFraction; tan(Y) = StartFraction Y Z Over X Y EndFraction sin(Y) = StartFraction X Y Over X Z EndFraction; cos(Y) = StartFraction X Z Over X Y EndFraction; tan(Y) = StartFraction Y Z Over X Z EndFraction sin(Y) = StartFraction X Z Over X Y EndFraction; cos(Y) = StartFraction Y Z Over X Y EndFraction; tan(Y) = StartFraction X Z Over Y Z EndFraction sin(Y) = StartFraction Y Z Over X Y EndFraction; cos(Y) = StartFraction X Z Over X Y EndFraction; tan(Y) = StartFraction X Z Over Y Z EndFraction

Answer 1

C, short answer

Explanation:

trust

Answer 2

`\sin Y= (XZ)/(XY)`

`\cos Y= (YZ)/(XY)`

`\tan Y= (XZ)/(YZ)`

Explanation:

Given

See attachment for triangle

Required

Find
`\sin, \cos` and
`\tan` of angle Y

For angle Y:

`Opposite = XZ`

`Adjacent = YZ`

`Hypotenuse = XY`

The
`\sin` of an angle is calculated as:

`\sin\theta = (Opposite)/(Hypotenuse)`

So:

`\sin Y= (XZ)/(XY)`

The
`\cos` of an angle is calculated as:

`\cos\theta = (Adjacent)/(Hypotenuse)`

So:

`\cos Y= (YZ)/(XY)`

The
`\tan` of an angle is calculated as:

`\tan\theta = (Opposite)/(Adjacent)`

So:

`\tan Y= (XZ)/(YZ)`