Question

Y=-4(x+5)^2-3 in standard form

Answer 1

y = -4x^2 - 40x - 103

Explanation:

to get the standard form, you have to formulate the equation as

y = ax^2 + bx + c

we have to expand the (x+5)^2

y = -4((x+5)^2) - 3 = -4(x^2 + 10x + 25) - 3 = -4x^2 - 40x - 100 - 3 = -4x^2 - 40x - 103