Question

Line p has an equation of y = x-4. Line q includes the point (-10, -3) and is perpendicular

to line p. What is the equation of line q?
Write the equation in slope-intercept form. Write the numbers in the equation as simplified
proper fractions, improper fractions, or integers.

Answer 1

y = - x - 13

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x - 4 ← is in slope- intercept form

with slope m = 1

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(1)` = - 1 , then

y = - x + c ← is the partial equation of line q

to find c substitute (- 10, - 3 ) into the partial equation

- 3 = 10 + c ⇒ c = - 3 - 10 = - 13

y = - x - 13 ← equation of line q