Question

Shaquana and her children went into a movie theater and she bought $53 worth of

candies and pretzels. Each candy costs $5 and each pretzel costs $3. She bought a
total of 13 candies and pretzels altogether. Determine the number of candies and the
number of pretzels that Shaquana bought.
Shaquana bought
candies and
Complete: 67%
pretzels.

Answer 1

∴ Shaquana bought 7 candies and 6 pretzels.

Explanation:

Suppose all the snacks she bought were candies.

13 × $5 = $65

$65 - $53 = $12

$5 - $3 = $2

$12 ÷ $2 = 6 pretzels

∴ Number of candies Shaquana bought

= 13 snacks - 6 pretzels

= 7 candies

Answer 2

6 pretzels and 5 candies

Explanation:

Let c be the number of candies and p the number of pretzels.

We can determine the total cost by multiplying the candy price by it's price, $5/candy. That would be $5*c. We can do the same for the pretzels: $3*p.

Thje total spent is: ($5)c + ($3)p = $53. Since the $ sign cancels out, let's rewrite this to simplify: 5c + 3p = 53.

We know that c + p = 13

Rearrange this to c = 13-p and then substitute this definition of c in the first equation:

5c + 3p = 53

5(13-p) +3p = 53

65 - 5p + 3p = 53

-2p = - 12

p = 6 Shaquana brought 6 pretzels.

Since c + p = 13, this means she bought 7 candies.

Check to see if this works:

Do 6 pretzels and 7 candies cost $53?

(6 prezels)*($3/pretzel) = $18

(7 candies)*($5/candy) = $35

Total = $53 YES