Question

Suppose to a scientist was able to construct a barometer with a liquid being twice denser than mercury, then how would the liquid raise at standard pressure?​

Answer 1

h = h₀/2, the liquid column rises half the height

Step-by-step explanation:

Pressure is defined as force per area,

P = F / A

in a barometer the force is the weights of the liquid column

F = W = mg

P = m g/A

if we use the definition of density

ρ =
`(m)/(A h)`

`(m)/(A)` = ρ h

we substitute

P = ρ g h

Let's use the index o for the mercury

P₀ = ρ₀ g h₀

when we change the liquid for another with

ρ = 2ρ₀

the pressure expression is

P = 2ρ₀ g h

in the problem they indicate that the pressure is equal to the initial P = P₀

we substitute

ρ₀ g h₀ = 2ρ₀ g h

h₀ = 2h

h = h₀/2

the liquid column rises half the height