Question

Two electrons are separated by a distance of 5 x 10^-5m. The charge of each electron is -1.602 x 10^-19C. Assume the Coulomb’s constant is 8.99 x 10^9N . m^2/C^2

!!Correct answer will get 20 points!!

Answer 1

Step-by-step explanation:

Given:

r = 5·10⁻⁵ m

q₁ = q₂ = | 1.602·10⁻¹⁹ | C - electron charge modulus

k = 8.99·10⁹ m² / C₂ - the Coulomb’s constant

_______________

F - ? - electron repulsion force

According to Coulomb's law:

F = k·q² / r²

F = 8.99·10⁹·(1.602·10⁻¹⁹)² / (5·10⁻⁵)² ≈ 9,23·10⁻²⁰ N