Answer:
Q29. ∠CAD = (180° - 92°) ÷ 2 (angle sum of triangle; base angles of an isosceles triangle)
= 44°
Q30. Since triangle ACD is an isosceles triangle,
∴ ∠ACD = ∠CAD = 44°
Q31. ∠ACB = 180° - 44° (adjacent angles on a straight line)
= 136°
Q32. ∠ABC = (180 °- 136°) ÷ 2 (angle sum of triangle; base angles of an isosceles triangle)
= 22°